[Leetcode] 1832. Check if the Sentence Is Pangram

https://leetcode.com/problems/check-if-the-sentence-is-pangram

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class Solution:
    def checkIfPangram(self, sentence: str) -> bool:
        alphabet = {
            'a':0, 'b':0, 'c':0, 'd':0, 'e':0, 'f':0, 'g':0, 'h':0, 'i':0, 
            'j':0, 'k':0, 'l':0, 'm':0, 'n':0, 'o':0, 'p':0, 'q':0, 'r':0, 
            's':0, 't':0, 'u':0, 'v':0, 'w':0, 'x':0, 'y':0, 'z':0
        }

        for n in sentence:
            alphabet[n] += 1

        for key, value in alphabet.items():
            if value == 0:
                return False

        return True